CUET General Aptitude Test PYQ || CUET GT Practice Question

Q. 56. $-\sqrt{8}+\sqrt{128}-\sqrt{32}$ is equal to

(A) $-2\sqrt{2}$

(B) $2\sqrt{2}$

(D) $3\sqrt{2}$

Answer:

(B)

2\sqrt{2}

Explanation:

Simplifying the surds:

-2\sqrt{2} + 8\sqrt{2} – 4\sqrt{2}

. Summing them yields

(-2 + 8 – 4)\sqrt{2} = 2\sqrt{2}

Q. 57. A clock seen through the mirror shows quarter to three. What is the correct time shown in the clock ?

(A) 8:15

(B) 9:15

(D) 9:45

Answer:

Explanation:

Q. 58. If P consumes 1500 ml of milk every day. How many liters of milk will be consumed in 4 weeks ?

(A) 42

(B) 40

(D) 36

Answer:

Explanation:

1500 ml equals 1.5 Liters per day. 4 weeks consists of 28 days. Total consumption =

1.5 \times 28 = 42

Liters.

Q. 59. Find the smallest among the following: $\sqrt [4] {6}$ , $\sqrt{2}$ , $\sqrt [3] {4}$ and $\sqrt{3}$

(A) $\sqrt[4]{6}$

(B) $\sqrt{2}$

(D) $\sqrt{3}$

Answer:

(B)

\sqrt{2}

Explanation:

Convert indices to a common denominator (12).

6^{3/12} = \sqrt{216}

;

2^{6/12} = \sqrt{64}

;

3^{4/12} = \sqrt{81}

. The smallest number inside the root is 64, which corresponds to

\sqrt{2}

Q. 60. The angle of depression of a point situated at a distance 500 m from the base of tower is $45^{\circ}$ . The height of tower is

(A) $\frac{500}{3}\sqrt{3}m$

(B) $500(\sqrt{3}+1)$ m

(D) 500 m

Answer:

Explanation:

The tangent of the angle equals the height over the base distance.

\tan(45^{\circ}) = \text{Height} / 500

. Since

\tan(45^{\circ}) = 1

, the Height is 500 m.

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