41. Sheetal is twice as good as workman as Babita and together they finish a piece of work in 18 days. Find the total number of days in which Babita can finish the work.
(A) 27 days
(B) 54 days
(C) 56 days
(D) 68 days
Answer:
(B) 54 days
Explanation:
Let Babita’s work rate be 1 unit/day; Sheetal’s is 2 units/day. Together they do 3 units/day. In 18 days, total work = 18×3=54 units. Babita alone would take 54/1=54 days.
42. The average weight of 39 Students in a class is 23. Among them Sita is the heaviest while Tina is the lightest. If both of them are excluded from the class still the average remains same. The ratio of weight of Sita to Tina is 15:8. Then what is the weight of the Tina?
(A) 15
(B) 16
(C) 18
(D) 19
Answer:
(B) 16
Explanation:
Since removing them doesn’t change the average (23), their combined weight must equal 2×23=46. Given the ratio 15:8, 15x+8x=23x=46 x=2. Tina’s weight is 8x=8×2=16.
43. In this question a series is given with one term missing. Choose the correct alternative from the given ones that will complete the series.
C J P ? Y B
(A) W
(B) U
(C) R
(D) T
Answer:
(B) U
Explanation:
Converting the letters to their alphabetical positions: C(3), J(10), P(16), ?, Y(25), B(2/28). The sequence of differences is +7, +6, +5, +4, +3. Therefore, P(16)+5=21, which is the letter U.
44. A boat goes 6 km an hour in still water, it takes thrice as much time in going the same distance against the current comparison to the direction of the current. Find the speed of the current.
(A) 3km/hr
(B) 5km/hr
(C) 8km/hr
(D) 9km/hr
Answer:
(A) 3km/hr
Explanation:
Let current speed be v. Time upstream = 3× Time downstream. Distance is constant, so D/(6−v)=3×D/(6+v). This simplifies to 6+v=3(6−v) 6+v=18−3v 4v=12 v=3 km/hr.
45. David weighs 56 kg. If he reduces his weight in the ratio 7:6, find his new weight. New weight is?
(A) 54 kg
(B) 43 kg
(C) 48 kg
(D) 40 kg
Answer:
(C) 48 kg
Explanation:
“Reduces weight in the ratio 7:6” means the new weight is 6/7 of the original weight. Therefore, 56×(6/7)=8×6=48 kg.
