91. Every time Deepa hits the target, she gets one rupee and every time she misses the target, she has to pay one rupee. She is allowed to try 100 times and gets an amount of Rs. 30. How many times did she hit the target?
(A) 35
(B) 65
(C) 80
(D) 75
Answer:
(B) 65
Explanation:
Let $x$ be the number of hits and $y$ be the misses. The total attempts are $x + y = 100$. The monetary result is $1(x) – 1(y) = 30$. Adding the two equations together: $2x = 130$. Solving for $x$ gives $x = 65$ hits.
92. Replace the question mark with the correct alternative 8, 27, 64, ?
(A) 216
(B) 125
(C) 64
(D) 224
Answer:
(B) 125
Explanation:
The sequence is formed by cubing consecutive integers: $2^3 = 8$; $3^3 = 27$; $4^3 = 64$. The next term must be $5^3 = 125$.
93. Complete the series:AZ, CX, FU, ?
(A) IR
(B) JQ
(C) IV
(D) KP
Answer:
(B) JQ
Explanation:
Break it down by letters. First letter: A (+2)= C (+3)= F (+4)= J. Second letter is the reverse alphabet counterpart: A opposes Z, C opposes X, F opposes U, so J opposes Q. Therefore, the next pair is JQ.
94. 1125 : 27 as 2511 : ?
(A) 36
(B) 63
(C) 72
(D) 81
Answer:
(C) 72
Explanation:
The relationship is created by adding the first pair of digits and the second pair of digits. In 1125: $(1+1=2)$ and $(2+5=7)$ -> forming 27. In 2511: $(2+5=7)$ and $(1+1=2)$ -> forming 72.
95. If you are the ninth person in the queue starting from either end, then the number of persons in the queue is :
(A) 19
(B) 17
(C) 10
(D) 18
Answer:
(B) 17
Explanation:
If you are 9th from the front, there are 8 people ahead of you. If you are 9th from the back, there are 8 people behind you. Therefore, the total is: 8 ahead + 1 (you) + 8 behind = 17 people.
