Categories: Jamia school entrance

JMI 11th Science Entrance Paper 2025 Answer Key

31. A piece of wire of resistance R is cut into five parts. These parts are then connected in parallel. If the equivalent resistance of this parallel combination is R’ then the ratio of R/R’ is

(A) R/R’ = 1/25
(B) R/R’ = 1/5
(C) R/R’ = 5
(D) R/R’ = 25

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32. An electric bulb is rated 220V and 100W. When it is operated on 110V the power consumed will be

(A) P = 25W
(B) P = 5OW
(C) P = 15W
(D) P = 20W

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33. Calculate the number of electrons constituting one coulomb of charge

(A) 6.50×1018
(C) 6.25×1018
(B) 6.00×1018
(D) 6.52×1018

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34. How much energy is given to each coulomb of charge passing through a 6V battery?

(A) E = 6J
(B) E = 12J
(C) E =18J
(D) E = 3J

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35. An electron beam enters a magnetic field at right angles to it. In which magnetic field is going horizontally right ward and electron beam is perpendicular downward. The direction of force acting on the electron beam Will be.

  • Magnetic field —————–>‫‫
  • Electron beam ↓↓↓↓↓↓↓↓↓↓↓

(A) to the left
(B) to the right
(C) into the page
(D) out of the page

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